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# 69. Sqrt(x)

<https://leetcode.com/problems/sqrtx>[/description/](https://leetcode.com/problems/climbing-stairs/description/)

Implement `int sqrt(int x)`.

Compute and return the square root of *x*, where *x* is guaranteed to be a non-negative integer.

Since the return type is an integer, the decimal digits are truncated and only the integer part of the result is returned.

**Example 1:**

```
Input: 4
Output: 2
```

**Example 2:**

```
Input: 8
Output: 2
Explanation: The square root of 8 is 2.82842..., and since 
             the decimal part is truncated, 2 is returned.
```

**Solution:**

```
class Solution(object):
    def mySqrt(self, x):
        """
        :type x: int
        :rtype: int
        """
        r = x
        while r*r>x:
            r = (r+x/r)/2
        return r
```