69. Sqrt(x)
https://leetcode.com/problems/sqrtx/description/
Implement int sqrt(int x)
.
Compute and return the square root of x, where x is guaranteed to be a non-negative integer.
Since the return type is an integer, the decimal digits are truncated and only the integer part of the result is returned.
Example 1:
Input: 4
Output: 2
Example 2:
Input: 8
Output: 2
Explanation: The square root of 8 is 2.82842..., and since
the decimal part is truncated, 2 is returned.
Solution:
class Solution(object):
def mySqrt(self, x):
"""
:type x: int
:rtype: int
"""
r = x
while r*r>x:
r = (r+x/r)/2
return r
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